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(4m+6)(3m+6)=0
We multiply parentheses ..
(+12m^2+24m+18m+36)=0
We get rid of parentheses
12m^2+24m+18m+36=0
We add all the numbers together, and all the variables
12m^2+42m+36=0
a = 12; b = 42; c = +36;
Δ = b2-4ac
Δ = 422-4·12·36
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6}{2*12}=\frac{-48}{24} =-2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6}{2*12}=\frac{-36}{24} =-1+1/2 $
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