1/8(3d-2)=1/(4d+51)

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Solution for 1/8(3d-2)=1/(4d+51) equation: 



1/8(3d-2)=1/(4d+51)

We move all terms to the left:

1/8(3d-2)-(1/(4d+51))=0



Domain of the equation: 8(3d-2)!=0

d∈R





Domain of the equation: (4d+51))!=0

d∈R



We calculate fractions


(1*(4d+51)))/(8(3d-2)*(4d+51)))+(-8d3/(8(3d-2)*(4d+51)))=0



We calculate terms in parentheses: +(1*(4d+51)))/(8(3d-2)*(4d+51)))+(-8d3/(8(3d-2)*(4d+51))), so:

1*(4d+51)))/(8(3d-2)*(4d+51)))+(-8d3/(8(3d-2)*(4d+51))

We add all the numbers together, and all the variables

1*(4d+51)))/(8(3d-2)*(4d+51)))+(-8d3/(8(3d-2)*(4d

We multiply all the terms by the denominator


1*(4d+51)))-2*4d*(8(3d+51)))+(-8d3-2*4d*(8(3d

Back to the equation:

+(1*(4d+51)))-2*4d*(8(3d+51)))+(-8d3-2*4d*(8(3d)

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