1/36x+24-20=-1/4(12x-72

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Solution for 1/36x+24-20=-1/4(12x-72 equation: 



1/36x+24-20=-1/4(12x-72

We move all terms to the left:

1/36x+24-20-(-1/4(12x-72)=0



Domain of the equation: 36x!=0

x!=0/36

x!=0

x∈R





Domain of the equation: 4(12x-72)+24-20!=0

We move all terms containing x to the left, all other terms to the right

4(12x-72)!=-4

x∈R



We calculate fractions


(4x(1+4)/(144x^2(1+4)+(-(-1*36x)/(144x^2(1+4)=0



We calculate terms in parentheses: +(4x(1+4)/(144x^2(1+4)+(-(-1*36x)/(144x^2(1+4), so:

4x(1+4)/(144x^2(1+4)+(-(-1*36x)/(144x^2(1+4

We can not solve this equation

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