30=t-3+2(t-3)

Solution for 30=t-3+2(t-3) equation:

30=t-3+2(t-3)

We move all terms to the left:

30-(t-3+2(t-3))=0


We calculate terms in parentheses: -(t-3+2(t-3)), so:

t-3+2(t-3)

determiningTheFunctionDomain
t+2(t-3)-3

We multiply parentheses

t+2t-6-3

We add all the numbers together, and all the variables

3t-9

Back to the equation:

-(3t-9)


We get rid of parentheses

-3t+9+30=0

We add all the numbers together, and all the variables

-3t+39=0

We move all terms containing t to the left, all other terms to the right

-3t=-39

t=-39/-3

t=+13