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1/5x+5=4-1/4x
We move all terms to the left:
1/5x+5-(4-1/4x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(-1/4x+4)+5=0
We get rid of parentheses
1/5x+1/4x-4+5=0
We calculate fractions
4x/20x^2+5x/20x^2-4+5=0
We add all the numbers together, and all the variables
4x/20x^2+5x/20x^2+1=0
We multiply all the terms by the denominator
4x+5x+1*20x^2=0
We add all the numbers together, and all the variables
9x+1*20x^2=0
Wy multiply elements
20x^2+9x=0
a = 20; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·20·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*20}=\frac{-18}{40} =-9/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*20}=\frac{0}{40} =0 $
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