1/5(x-8)+(4+x)/4+(x-1)/7=7-(23-x)/5

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Solution for 1/5(x-8)+(4+x)/4+(x-1)/7=7-(23-x)/5 equation: 



1/5(x-8)+(4+x)/4+(x-1)/7=7-(23-x)/5

We move all terms to the left:

1/5(x-8)+(4+x)/4+(x-1)/7-(7-(23-x)/5)=0



Domain of the equation: 5(x-8)!=0

x∈R



We add all the numbers together, and all the variables

1/5(x-8)+(x+4)/4+(x-1)/7-(7-(-1x+23)/5)=0

We calculate fractions


()/5x+((x+4)*5(x-8)*7*5))/5x+((x-1)*5(x-8)*4*5))/5x+(-(7-(-1x+23)*5(x-8)*4*7)/5x=0

We can not solve this equation

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