30v2+65v+30=0

Solution for 30v2+65v+30=0 equation:

30v^2+65v+30=0

a = 30; b = 65; c = +30;
Δ = b2-4ac
Δ = 652-4·30·30
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-25}{2*30}=\frac{-90}{60}
=-1+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+25}{2*30}=\frac{-40}{60}
=-2/3
$