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1/5(6t-4)=1/10(t+4)
We move all terms to the left:
1/5(6t-4)-(1/10(t+4))=0
Domain of the equation: 5(6t-4)!=0
t∈R
Domain of the equation: 10(t+4))!=0We calculate fractions
t∈R
(10tt/(5(6t-4)*10(t+4)))+(-5t6/(5(6t-4)*10(t+4)))=0
We calculate terms in parentheses: +(10tt/(5(6t-4)*10(t+4))), so:
10tt/(5(6t-4)*10(t+4))
We multiply all the terms by the denominator
10tt
Back to the equation:
+(10tt)
We calculate terms in parentheses: +(-5t6/(5(6t-4)*10(t+4))), so:
-5t6/(5(6t-4)*10(t+4))
We multiply all the terms by the denominator
-5t6
We add all the numbers together, and all the variables
-5t^6
We do not support etpression: t^6
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