16x=(-2/3)+25

Solution for 16x=(-2/3)+25 equation:

16x=(-2/3)+25

We move all terms to the left:

16x-((-2/3)+25)=0

We multiply all the terms by the denominator


16x*3)+25)-((-2=0

Wy multiply elements

48x^2-2=0

a = 48; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·48·(-2)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*48}=\frac{0-8\sqrt{6}}{96}
=-\frac{8\sqrt{6}}{96}
=-\frac{\sqrt{6}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*48}=\frac{0+8\sqrt{6}}{96}
=\frac{8\sqrt{6}}{96}
=\frac{\sqrt{6}}{12}
$