-2(n+2)=-4(1+n)+6n

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Solution for -2(n+2)=-4(1+n)+6n equation: 



-2(n+2)=-4(1+n)+6n

We move all terms to the left:

-2(n+2)-(-4(1+n)+6n)=0

We add all the numbers together, and all the variables

-2(n+2)-(-4(n+1)+6n)=0

We multiply parentheses

-2n-(-4(n+1)+6n)-4=0



We calculate terms in parentheses: -(-4(n+1)+6n), so:

-4(n+1)+6n

We add all the numbers together, and all the variables

6n-4(n+1)

We multiply parentheses

6n-4n-4

We add all the numbers together, and all the variables

2n-4

Back to the equation:

-(2n-4)



We get rid of parentheses

-2n-2n+4-4=0

We add all the numbers together, and all the variables

-4n=0

n=0/-4

n=0

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