6(x-1)/9=4(x+2)/12

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Solution for 6(x-1)/9=4(x+2)/12 equation:



6(x-1)/9=4(x+2)/12
We move all terms to the left:
6(x-1)/9-(4(x+2)/12)=0
We calculate fractions
6x/()+(-(4(x+2)*9)/()=0
We calculate terms in parentheses: +(-(4(x+2)*9)/(), so:
-(4(x+2)*9)/(
We multiply all the terms by the denominator
-(4(x+2)*9)
We calculate terms in parentheses: -(4(x+2)*9), so:
4(x+2)*9
We multiply parentheses
36x+72
Back to the equation:
-(36x+72)
We get rid of parentheses
-36x-72
Back to the equation:
+(-36x-72)
We get rid of parentheses
6x/()-36x-72=0
We multiply all the terms by the denominator
6x-36x*()-72*()=0
We add all the numbers together, and all the variables
6x-36x*()=0

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