1/5(3-x)+1/2(2x+1)=3/10

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Solution for 1/5(3-x)+1/2(2x+1)=3/10 equation: 



1/5(3-x)+1/2(2x+1)=3/10

We move all terms to the left:

1/5(3-x)+1/2(2x+1)-(3/10)=0



Domain of the equation: 5(3-x)!=0

x∈R





Domain of the equation: 2(2x+1)!=0

x∈R



We add all the numbers together, and all the variables

1/5(-1x+3)+1/2(2x+1)-(+3/10)=0

We get rid of parentheses

1/5(-1x+3)+1/2(2x+1)-3/10=0

We calculate fractions


(20x2/(5(-1x+3)*2(2x+1)*10)+(50x(-)/(5(-1x+3)*2(2x+1)*10)+(-30x^2(-)/(5(-1x+3)*2(2x+1)*10)=0



We calculate terms in parentheses: +(20x2/(5(-1x+3)*2(2x+1)*10)+(50x(-)/(5(-1x+3)*2(2x+1)*10)+(-30x^2(-)/(5(-1x+3)*2(2x+1)*10), so:

20x2/(5(-1x+3)*2(2x+1)*10)+(50x(-)/(5(-1x+3)*2(2x+1)*10)+(-30x^2(-)/(5(-1x+3)*2(2x+1)*10

We can not solve this equation

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