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(x+6)(4x-9)=0
We multiply parentheses ..
(+4x^2-9x+24x-54)=0
We get rid of parentheses
4x^2-9x+24x-54=0
We add all the numbers together, and all the variables
4x^2+15x-54=0
a = 4; b = 15; c = -54;
Δ = b2-4ac
Δ = 152-4·4·(-54)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-33}{2*4}=\frac{-48}{8} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+33}{2*4}=\frac{18}{8} =2+1/4 $
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