11(z+4)-3(z-3)=5(z-2)+2(z-2)

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Solution for 11(z+4)-3(z-3)=5(z-2)+2(z-2) equation: 



11(z+4)-3(z-3)=5(z-2)+2(z-2)

We move all terms to the left:

11(z+4)-3(z-3)-(5(z-2)+2(z-2))=0

We multiply parentheses

11z-3z-(5(z-2)+2(z-2))+44+9=0



We calculate terms in parentheses: -(5(z-2)+2(z-2)), so:

5(z-2)+2(z-2)

We multiply parentheses

5z+2z-10-4

We add all the numbers together, and all the variables

7z-14

Back to the equation:

-(7z-14)



We add all the numbers together, and all the variables

8z-(7z-14)+53=0

We get rid of parentheses

8z-7z+14+53=0

We add all the numbers together, and all the variables

z+67=0

We move all terms containing z to the left, all other terms to the right

z=-67

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