1/5(3+2z)=-3

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Solution for 1/5(3+2z)=-3 equation: 



1/5(3+2z)=-3

We move all terms to the left:

1/5(3+2z)-(-3)=0



Domain of the equation: 5(3+2z)!=0

z∈R



We add all the numbers together, and all the variables

1/5(2z+3)-(-3)=0

We add all the numbers together, and all the variables

1/5(2z+3)+3=0

We multiply all the terms by the denominator


3*5(2z+3)+1=0

Wy multiply elements

15z(2+1=0

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