0.4x+0.25(128-x)=31

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Solution for 0.4x+0.25(128-x)=31 equation: 



0.4x+0.25(128-x)=31

We move all terms to the left:

0.4x+0.25(128-x)-(31)=0

We add all the numbers together, and all the variables

0.4x+0.25(-1x+128)-31=0

We multiply parentheses

0.4x-0.25x+32-31=0

We add all the numbers together, and all the variables

0.15x+1=0

We move all terms containing x to the left, all other terms to the right

0.15x=-1

x=-1/0.15

x=-6+0.1/0.15

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