3(x+4)+7=8(x-2)

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Solution for 3(x+4)+7=8(x-2) equation: 



3(x+4)+7=8(x-2)

We move all terms to the left:

3(x+4)+7-(8(x-2))=0

We multiply parentheses

3x-(8(x-2))+12+7=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We add all the numbers together, and all the variables

3x-(8x-16)+19=0

We get rid of parentheses

3x-8x+16+19=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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