1/5(10x+30)-4=-1/4(12x-48)

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Solution for 1/5(10x+30)-4=-1/4(12x-48) equation: 



1/5(10x+30)-4=-1/4(12x-48)

We move all terms to the left:

1/5(10x+30)-4-(-1/4(12x-48))=0



Domain of the equation: 5(10x+30)!=0

x∈R





Domain of the equation: 4(12x-48))!=0

x∈R



We calculate fractions


(4x1/(5(10x+30)*4(12x-48)))+(-(-5x1)/(5(10x+30)*4(12x-48)))-4=0



We calculate terms in parentheses: +(4x1/(5(10x+30)*4(12x-48))), so:

4x1/(5(10x+30)*4(12x-48))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-(-5x1)/(5(10x+30)*4(12x-48))), so:

-(-5x1)/(5(10x+30)*4(12x-48))

We add all the numbers together, and all the variables

-(-5x)/(5(10x+30)*4(12x-48))

We multiply all the terms by the denominator


-(-5x)

We get rid of parentheses

5x

Back to the equation:

+(5x)



We add all the numbers together, and all the variables

9x-4=0

We move all terms containing x to the left, all other terms to the right

9x=4

x=4/9

x=4/9

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