m=-(4+m)+2m=+2

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Solution for m=-(4+m)+2m=+2 equation: 



m=-(4+m)+2m=+2

We move all terms to the left:

m-(-(4+m)+2m)=0

We add all the numbers together, and all the variables

m-(-(m+4)+2m)=0



We calculate terms in parentheses: -(-(m+4)+2m), so:

-(m+4)+2m

We add all the numbers together, and all the variables

2m-(m+4)

We get rid of parentheses

2m-m-4

We add all the numbers together, and all the variables

m-4

Back to the equation:

-(m-4)



We get rid of parentheses

m-m+4=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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