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1/3(15x+27)-16=-1/2(6x-18)
We move all terms to the left:
1/3(15x+27)-16-(-1/2(6x-18))=0
Domain of the equation: 3(15x+27)!=0
x∈R
Domain of the equation: 2(6x-18))!=0We calculate fractions
x∈R
(2x6/(3(15x+27)*2(6x-18)))+(-(-3x1)/(3(15x+27)*2(6x-18)))-16=0
We calculate terms in parentheses: +(2x6/(3(15x+27)*2(6x-18))), so:
2x6/(3(15x+27)*2(6x-18))
We multiply all the terms by the denominator
2x6
We add all the numbers together, and all the variables
2x^6
We do not support expression: x^6
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