1/4(8x-4)=1/3(12x+3)

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Solution for 1/4(8x-4)=1/3(12x+3) equation: 



1/4(8x-4)=1/3(12x+3)

We move all terms to the left:

1/4(8x-4)-(1/3(12x+3))=0



Domain of the equation: 4(8x-4)!=0

x∈R





Domain of the equation: 3(12x+3))!=0

x∈R



We calculate fractions


(3x1/(4(8x-4)*3(12x+3)))+(-4x8/(4(8x-4)*3(12x+3)))=0



We calculate terms in parentheses: +(3x1/(4(8x-4)*3(12x+3))), so:

3x1/(4(8x-4)*3(12x+3))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-4x8/(4(8x-4)*3(12x+3))), so:

-4x8/(4(8x-4)*3(12x+3))

We multiply all the terms by the denominator


-4x8

We add all the numbers together, and all the variables

-4x^8

We do not support expression: x^8

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