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1/4(6x+48)-20=-1/3(4x-72
We move all terms to the left:
1/4(6x+48)-20-(-1/3(4x-72)=0
Domain of the equation: 4(6x+48)!=0
x∈R
Domain of the equation: 3(4x-72)-20!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
3(4x-72)!=20
x∈R
(3x(4-20)/(4(6x+48)*3(4x-72)-20)+(-(-4x6)/(4(6x+48)*3(4x-72)-20)=0
We calculate terms in parentheses: +(3x(4-20)/(4(6x+48)*3(4x-72)-20)+(-(-4x6)/(4(6x+48)*3(4x-72)-20), so:
3x(4-20)/(4(6x+48)*3(4x-72)-20)+(-(-4x6)/(4(6x+48)*3(4x-72)-20
We add all the numbers together, and all the variables
(-(-4x^6)/(4(6x+48)*3(4x-72)-20+3x(-16)/(4(6x+48)*3(4x-72)-20)
We can not solve this equation
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