4(3+4)=-8(2r+5)

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Solution for 4(3+4)=-8(2r+5) equation: 



4(3+4)=-8(2r+5)

We move all terms to the left:

4(3+4)-(-8(2r+5))=0

We add all the numbers together, and all the variables

-(-8(2r+5))+47=0



We calculate terms in parentheses: -(-8(2r+5)), so:

-8(2r+5)

We multiply parentheses

-16r-40

Back to the equation:

-(-16r-40)



We get rid of parentheses

16r+40+47=0

We add all the numbers together, and all the variables

16r+87=0

We move all terms containing r to the left, all other terms to the right

16r=-87

r=-87/16

r=-5+7/16

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