8y+4(y-6)=-20

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Solution for 8y+4(y-6)=-20 equation: 



8y+4(y-6)=-20

We move all terms to the left:

8y+4(y-6)-(-20)=0

We add all the numbers together, and all the variables

8y+4(y-6)+20=0

We multiply parentheses

8y+4y-24+20=0

We add all the numbers together, and all the variables

12y-4=0

We move all terms containing y to the left, all other terms to the right

12y=4

y=4/12

y=1/3

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