1/4(20a-4a)=6-a

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Solution for 1/4(20a-4a)=6-a equation: 



1/4(20a-4a)=6-a

We move all terms to the left:

1/4(20a-4a)-(6-a)=0



Domain of the equation: 4(20a-4a)!=0

a∈R



We add all the numbers together, and all the variables

1/4(+16a)-(-1a+6)=0

We get rid of parentheses

1/4(+16a)+1a-6=0

We multiply all the terms by the denominator


1a*4(+16a)-6*4(+16a)+1=0

Wy multiply elements

4a^2(+-24a(++1=0

We use the square of the difference formula

4a^2(-24a(+1=0

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