1/4(12-20x)=3+-5x

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Solution for 1/4(12-20x)=3+-5x equation: 



1/4(12-20x)=3+-5x

We move all terms to the left:

1/4(12-20x)-(3+-5x)=0



Domain of the equation: 4(12-20x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(-20x+12)-(-5x)=0

We get rid of parentheses

1/4(-20x+12)+5x=0

We multiply all the terms by the denominator


5x*4(-20x+12)+1=0

Wy multiply elements

20x^2(-+1=0

We use the square of the difference formula

20x^2(-1=0

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