36x(2)+18x+2=0

Solution for 36x(2)+18x+2=0 equation:

36x(2)+18x+2=0

We add all the numbers together, and all the variables

36x^2+18x+2=0

a = 36; b = 18; c = +2;
Δ = b2-4ac
Δ = 182-4·36·2
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*36}=\frac{-24}{72}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*36}=\frac{-12}{72}
=-1/6
$