1/4(-3y+7)=2/5(8-3y)

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Solution for 1/4(-3y+7)=2/5(8-3y) equation: 



1/4(-3y+7)=2/5(8-3y)

We move all terms to the left:

1/4(-3y+7)-(2/5(8-3y))=0



Domain of the equation: 4(-3y+7)!=0

y∈R





Domain of the equation: 5(8-3y))!=0

y∈R



We add all the numbers together, and all the variables

1/4(-3y+7)-(2/5(-3y+8))=0

We calculate fractions


(5y(-)/(4(-3y+7)*5(-3y+8)))+(-8y0/(4(-3y+7)*5(-3y+8)))=0



We calculate terms in parentheses: +(5y(-)/(4(-3y+7)*5(-3y+8))), so:

5y(-)/(4(-3y+7)*5(-3y+8))

We add all the numbers together, and all the variables

5y0/(4(-3y+7)*5(-3y+8))

We multiply all the terms by the denominator


5y0

We add all the numbers together, and all the variables

5y

Back to the equation:

+(5y)





We calculate terms in parentheses: +(-8y0/(4(-3y+7)*5(-3y+8))), so:

-8y0/(4(-3y+7)*5(-3y+8))

We multiply all the terms by the denominator


-8y0

We add all the numbers together, and all the variables

-8y

Back to the equation:

+(-8y)



We get rid of parentheses

5y-8y=0

We add all the numbers together, and all the variables

-3y=0

y=0/-3

y=0

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