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1/3x-3=5/3+x+-5
We move all terms to the left:
1/3x-3-(5/3+x+-5)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3+x+-5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x+-5)!=-3
x∈R
1/3x-(x+5/3-5)-3=0
We get rid of parentheses
1/3x-x+5-3-5/3=0
We calculate fractions
-x+5-3=0
We add all the numbers together, and all the variables
-1x+2=0
We move all terms containing x to the left, all other terms to the right
-x=-2
x=-2/-1
x=+2
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