7x-2(3+4x)=28

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Solution for 7x-2(3+4x)=28 equation: 



7x-2(3+4x)=28

We move all terms to the left:

7x-2(3+4x)-(28)=0

We add all the numbers together, and all the variables

7x-2(4x+3)-28=0

We multiply parentheses

7x-8x-6-28=0

We add all the numbers together, and all the variables

-1x-34=0

We move all terms containing x to the left, all other terms to the right

-x=34

x=34/-1

x=-34

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