1/3x+2=1/5x+1

Solution for 1/3x+2=1/5x+1 equation:

1/3x+2=1/5x+1

We move all terms to the left:

1/3x+2-(1/5x+1)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 5x+1)!=0

x∈R


We get rid of parentheses

1/3x-1/5x-1+2=0

We calculate fractions


5x/15x^2+(-3x)/15x^2-1+2=0

We add all the numbers together, and all the variables

5x/15x^2+(-3x)/15x^2+1=0

We multiply all the terms by the denominator


5x+(-3x)+1*15x^2=0

Wy multiply elements

15x^2+5x+(-3x)=0

We get rid of parentheses

15x^2+5x-3x=0

We add all the numbers together, and all the variables

15x^2+2x=0

a = 15; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·15·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*15}=\frac{-4}{30}
=-2/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*15}=\frac{0}{30}
=0
$