67-5(x-15)=6x+8(x-5)

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Solution for 67-5(x-15)=6x+8(x-5) equation: 



67-5(x-15)=6x+8(x-5)

We move all terms to the left:

67-5(x-15)-(6x+8(x-5))=0

We multiply parentheses

-5x-(6x+8(x-5))+75+67=0



We calculate terms in parentheses: -(6x+8(x-5)), so:

6x+8(x-5)

We multiply parentheses

6x+8x-40

We add all the numbers together, and all the variables

14x-40

Back to the equation:

-(14x-40)



We add all the numbers together, and all the variables

-5x-(14x-40)+142=0

We get rid of parentheses

-5x-14x+40+142=0

We add all the numbers together, and all the variables

-19x+182=0

We move all terms containing x to the left, all other terms to the right

-19x=-182

x=-182/-19

x=9+11/19

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