67-5(x-4)=6x+9(x-7)

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Solution for 67-5(x-4)=6x+9(x-7) equation: 



67-5(x-4)=6x+9(x-7)

We move all terms to the left:

67-5(x-4)-(6x+9(x-7))=0

We multiply parentheses

-5x-(6x+9(x-7))+20+67=0



We calculate terms in parentheses: -(6x+9(x-7)), so:

6x+9(x-7)

We multiply parentheses

6x+9x-63

We add all the numbers together, and all the variables

15x-63

Back to the equation:

-(15x-63)



We add all the numbers together, and all the variables

-5x-(15x-63)+87=0

We get rid of parentheses

-5x-15x+63+87=0

We add all the numbers together, and all the variables

-20x+150=0

We move all terms containing x to the left, all other terms to the right

-20x=-150

x=-150/-20

x=7+1/2

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