1/3f+5/6f=14

Solution for 1/3f+5/6f=14 equation:

1/3f+5/6f=14

We move all terms to the left:

1/3f+5/6f-(14)=0


Domain of the equation: 3f!=0

f!=0/3

f!=0

f∈R



Domain of the equation: 6f!=0

f!=0/6

f!=0

f∈R


We calculate fractions


6f/18f^2+15f/18f^2-14=0

We multiply all the terms by the denominator


6f+15f-14*18f^2=0

We add all the numbers together, and all the variables

21f-14*18f^2=0

Wy multiply elements

-252f^2+21f=0

a = -252; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·(-252)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*-252}=\frac{-42}{-504}
=1/12
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*-252}=\frac{0}{-504}
=0
$