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5(x+1)=3(2x+4)
We move all terms to the left:
5(x+1)-(3(2x+4))=0
We multiply parentheses
5x-(3(2x+4))+5=0
We calculate terms in parentheses: -(3(2x+4)), so:We get rid of parentheses
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
5x-6x-12+5=0
We add all the numbers together, and all the variables
-1x-7=0
We move all terms containing x to the left, all other terms to the right
-x=7
x=7/-1
x=-7
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