4t(t+1)=6t-1

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Solution for 4t(t+1)=6t-1 equation: 



4t(t+1)=6t-1

We move all terms to the left:

4t(t+1)-(6t-1)=0

We multiply parentheses

4t^2+4t-(6t-1)=0

We get rid of parentheses

4t^2+4t-6t+1=0

We add all the numbers together, and all the variables

4t^2-2t+1=0

a = 4; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·4·1
Δ = -12
Delta is less than zero, so there is no solution for the equation

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