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1/3(z+9)-6=5
We move all terms to the left:
1/3(z+9)-6-(5)=0
Domain of the equation: 3(z+9)!=0We add all the numbers together, and all the variables
z∈R
1/3(z+9)-11=0
We multiply all the terms by the denominator
-11*3(z+9)+1=0
Wy multiply elements
-33z(z+1=0
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