4(m+3)=20+m

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Solution for 4(m+3)=20+m equation: 



4(m+3)=20+m

We move all terms to the left:

4(m+3)-(20+m)=0

We add all the numbers together, and all the variables

4(m+3)-(m+20)=0

We multiply parentheses

4m-(m+20)+12=0

We get rid of parentheses

4m-m-20+12=0

We add all the numbers together, and all the variables

3m-8=0

We move all terms containing m to the left, all other terms to the right

3m=8

m=8/3

m=2+2/3

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