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1/3(9m-5)+2=2+3(m-15)
We move all terms to the left:
1/3(9m-5)+2-(2+3(m-15))=0
Domain of the equation: 3(9m-5)!=0We multiply all the terms by the denominator
m∈R
-((2+3(m-15)))*3(9m-5)+2*3(9m-5)+1=0
We calculate terms in parentheses: -((2+3(m-15)))*3(9m-5), so:Wy multiply elements
(2+3(m-15)))*3(9m-5
-((2+3(m-15)))*3(9m-5)+6m(9+1=0
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(2+3(m-15)))*3(9m-5
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