6(y+4)=-6(2y-3)+y

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Solution for 6(y+4)=-6(2y-3)+y equation: 



6(y+4)=-6(2y-3)+y

We move all terms to the left:

6(y+4)-(-6(2y-3)+y)=0

We multiply parentheses

6y-(-6(2y-3)+y)+24=0



We calculate terms in parentheses: -(-6(2y-3)+y), so:

-6(2y-3)+y

We add all the numbers together, and all the variables

y-6(2y-3)

We multiply parentheses

y-12y+18

We add all the numbers together, and all the variables

-11y+18

Back to the equation:

-(-11y+18)



We get rid of parentheses

6y+11y-18+24=0

We add all the numbers together, and all the variables

17y+6=0

We move all terms containing y to the left, all other terms to the right

17y=-6

y=-6/17

y=-6/17

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