13(9m-5)+2=2+3(m-1/5)

Solution for 13(9m-5)+2=2+3(m-1/5) equation:

13(9m-5)+2=2+3(m-1/5)

We move all terms to the left:

13(9m-5)+2-(2+3(m-1/5))=0

We add all the numbers together, and all the variables

13(9m-5)-(2+3(+m-1/5))+2=0

We multiply parentheses

117m-(2+3(+m-1/5))-65+2=0

We multiply all the terms by the denominator


117m*5))-(2+3(+m-1-65*5))+2*5))=0

We add all the numbers together, and all the variables

117m*5))-(2+3(m-326))+2*5))=0

We add all the numbers together, and all the variables

117m*5))-(2+3(m=0

Wy multiply elements

585m^2=0

a = 585; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·585·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{1170}=0$