1/3(2y-3)=y+2

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Solution for 1/3(2y-3)=y+2 equation: 



1/3(2y-3)=y+2

We move all terms to the left:

1/3(2y-3)-(y+2)=0



Domain of the equation: 3(2y-3)!=0

y∈R



We get rid of parentheses

1/3(2y-3)-y-2=0

We multiply all the terms by the denominator


-y*3(2y-3)-2*3(2y-3)+1=0

Wy multiply elements

-3y^2(2-6y(2+1=0

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