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1/3(2x-1)=3/4(x=2)
We move all terms to the left:
1/3(2x-1)-(3/4(x)=0
Domain of the equation: 3(2x-1)!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
4x/(24x^2-12x)+(-9x2/(24x^2-12x)=0
We calculate terms in parentheses: +(-9x2/(24x^2-12x), so:We get rid of parentheses
-9x2/(24x^2-12x
We multiply all the terms by the denominator
-9x2
We add all the numbers together, and all the variables
-9x^2
Back to the equation:
+(-9x^2)
-9x^2+4x/(24x^2-12x)=0
We multiply all the terms by the denominator
-9x^2*(24x^2-12x)+4x=0
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