1/3(2x+5)-2=1/2(x+2)

Solution for 1/3(2x+5)-2=1/2(x+2) equation:

1/3(2x+5)-2=1/2(x+2)

We move all terms to the left:

1/3(2x+5)-2-(1/2(x+2))=0


Domain of the equation: 3(2x+5)!=0

x∈R



Domain of the equation: 2(x+2))!=0

x∈R


We calculate fractions


(2xx/(3(2x+5)*2(x+2)))+(-3x2/(3(2x+5)*2(x+2)))-2=0


We calculate terms in parentheses: +(2xx/(3(2x+5)*2(x+2))), so:

2xx/(3(2x+5)*2(x+2))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)



We calculate terms in parentheses: +(-3x2/(3(2x+5)*2(x+2))), so:

-3x2/(3(2x+5)*2(x+2))

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)


We get rid of parentheses

-3x^2+2xx-2=0

We move all terms containing x to the left, all other terms to the right

-3x^2+2xx=2