4(v+6)+3(v+2)=51

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Solution for 4(v+6)+3(v+2)=51 equation: 



4(v+6)+3(v+2)=51

We move all terms to the left:

4(v+6)+3(v+2)-(51)=0

We multiply parentheses

4v+3v+24+6-51=0

We add all the numbers together, and all the variables

7v-21=0

We move all terms containing v to the left, all other terms to the right

7v=21

v=21/7

v=3

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