(X-3)2+(y+1)2=13

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Solution for (X-3)2+(y+1)2=13 equation: 



(X-3)2+(X+1)2=13

We move all terms to the left:

(X-3)2+(X+1)2-(13)=0

We multiply parentheses

2X+2X-6+2-13=0

We add all the numbers together, and all the variables

4X-17=0

We move all terms containing X to the left, all other terms to the right

4X=17

X=17/4

X=4+1/4

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