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1/2x-6=-7+6x
We move all terms to the left:
1/2x-6-(-7+6x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(6x-7)-6=0
We get rid of parentheses
1/2x-6x+7-6=0
We multiply all the terms by the denominator
-6x*2x+7*2x-6*2x+1=0
Wy multiply elements
-12x^2+14x-12x+1=0
We add all the numbers together, and all the variables
-12x^2+2x+1=0
a = -12; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-12)·1
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{13}}{2*-12}=\frac{-2-2\sqrt{13}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{13}}{2*-12}=\frac{-2+2\sqrt{13}}{-24} $
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