5(a+3)-a=(a-6)+1

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Solution for 5(a+3)-a=(a-6)+1 equation: 



5(a+3)-a=(a-6)+1

We move all terms to the left:

5(a+3)-a-((a-6)+1)=0

We add all the numbers together, and all the variables

-1a+5(a+3)-((a-6)+1)=0

We multiply parentheses

-1a+5a-((a-6)+1)+15=0



We calculate terms in parentheses: -((a-6)+1), so:

(a-6)+1

We get rid of parentheses

a-6+1

We add all the numbers together, and all the variables

a-5

Back to the equation:

-(a-5)



We add all the numbers together, and all the variables

4a-(a-5)+15=0

We get rid of parentheses

4a-a+5+15=0

We add all the numbers together, and all the variables

3a+20=0

We move all terms containing a to the left, all other terms to the right

3a=-20

a=-20/3

a=-6+2/3

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