1/2x+7=x-8

Solution for 1/2x+7=x-8 equation:

1/2x+7=x-8

We move all terms to the left:

1/2x+7-(x-8)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-x+8+7=0

We multiply all the terms by the denominator


-x*2x+8*2x+7*2x+1=0

Wy multiply elements

-2x^2+16x+14x+1=0

We add all the numbers together, and all the variables

-2x^2+30x+1=0

a = -2; b = 30; c = +1;
Δ = b2-4ac
Δ = 302-4·(-2)·1
Δ = 908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{908}=\sqrt{4*227}=\sqrt{4}*\sqrt{227}=2\sqrt{227}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{227}}{2*-2}=\frac{-30-2\sqrt{227}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{227}}{2*-2}=\frac{-30+2\sqrt{227}}{-4}
$