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-(2x-2)-1=-x(x+3)
We move all terms to the left:
-(2x-2)-1-(-x(x+3))=0
We get rid of parentheses
-2x-(-x(x+3))+2-1=0
We calculate terms in parentheses: -(-x(x+3)), so:We add all the numbers together, and all the variables
-x(x+3)
We multiply parentheses
-x^2-3x
We add all the numbers together, and all the variables
-1x^2-3x
Back to the equation:
-(-1x^2-3x)
-(-1x^2-3x)-2x+1=0
We get rid of parentheses
1x^2+3x-2x+1=0
We add all the numbers together, and all the variables
x^2+x+1=0
a = 1; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·1·1
Δ = -3
Delta is less than zero, so there is no solution for the equation
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